Factors, Multiples & Divisibility
Numbers have families! Discover factors and multiples, spot primes in a flash, grow factor trees, find HCF and LCM, and use divisibility rules to crack missing-digit puzzles.
1Factors
A factor of a number divides it exactly, leaving no remainder. 4 is a factor of 12 because 12 รท 4 = 3 with remainder 0. 5 is not a factor of 12.
Factors come in pairs that multiply to give the number. To find all factors, start from 1 and test 1, 2, 3, โฆ until the pairs start to repeat.
Find all the factors of 48.
- 1 ร 48, 2 ร 24, 3 ร 16, 4 ร 12, 6 ร 8.
- 5 and 7 do not divide 48. Next to test is 8 โ but 8 is already in a pair, so stop.
- Factors: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48 โ 10 factors.
- 1 is a factor of every number. Every number is a factor of itself.
- The smallest factor is 1, and the greatest factor is the number itself.
- A number has a limited (finite) number of factors.
- Only special numbers (square numbers like 36, 49, 100) have an odd number of factors, because one pair uses the same number twice.
How many factors does 28 have?
2Multiples
A multiple of a number is what you get when you multiply it by 1, 2, 3, 4 โฆ Multiples of 7: 7, 14, 21, 28, 35, โฆ (its times table).
- Every number is a multiple of itself (ร1) โ that is its smallest multiple.
- A number has unlimited (infinite) multiples. There is no greatest multiple.
- Factors and multiples are partners: 4 is a factor of 12 โ 12 is a multiple of 4.
How many multiples of 6 lie between 40 and 80?
- First multiple after 40: 6 ร 7 = 42. Last multiple before 80: 6 ร 13 = 78.
- They are 6 ร 7, 6 ร 8, โฆ , 6 ร 13. Count from 7 to 13: 13 โ 7 + 1 = 7 multiples.
- List to check: 42, 48, 54, 60, 66, 72, 78 โ
"Between 40 and 80" does not include 40 and 80 themselves. If a question asks for multiples of 8 between 40 and 80, the answer is 48, 56, 64, 72 โ only 4, because 40 and 80 are left out.
3Even and odd, prime and composite
- Even numbers are multiples of 2 (end in 0, 2, 4, 6, 8). Odd numbers end in 1, 3, 5, 7, 9.
- even + even = even ยท odd + odd = even ยท even + odd = odd ยท odd ร odd = odd ยท even ร anything = even.
- A prime number has exactly two factors: 1 and itself. Examples: 2, 3, 5, 7, 11, 13.
- A composite number has more than two factors. Examples: 4, 6, 8, 9, 10, 12.
1 is neither prime nor composite โ it has only one factor. 2 is the smallest prime and the only even prime; every other even number has 2 as an extra factor, so it is composite. Also: the smallest composite number is 4, the smallest odd prime is 3, and the smallest odd composite is 9.
Check if it divides by 2, 3, 5 or 7. If none of them divides it, it is prime. Beware of numbers that look prime: 51 = 3 ร 17, 57 = 3 ร 19, 87 = 3 ร 29, 91 = 7 ร 13.
| Range | Primes | How many |
|---|---|---|
| 1 โ 10 | 2, 3, 5, 7 | 4 |
| 11 โ 20 | 11, 13, 17, 19 | 4 |
| 21 โ 50 | 23, 29, 31, 37, 41, 43, 47 | 7 |
| 51 โ 100 | 53, 59, 61, 67, 71, 73, 79, 83, 89, 97 | 10 |
Twin primes and co-primes
- Twin primes
- Two primes with a difference of 2: (3, 5), (5, 7), (11, 13), (17, 19), (29, 31), (41, 43), (59, 61), (71, 73).
- Co-primes
- Two numbers whose only common factor is 1, like 8 and 15. They do not need to be prime themselves! Any two consecutive numbers (like 20 and 21) are always co-prime, and so are any two different primes.
Which of these is a prime number?
4Factor trees and prime factorisation
Every composite number can be written as a product of primes. This is its prime factorisation. A factor tree helps: split the number into any two factors, then keep splitting until every branch ends in a prime.
Find the prime factorisation of 90 by dividing by primes.
- 90 is even: 90 รท 2 = 45.
- 45: digit sum 9, so divide by 3: 45 รท 3 = 15.
- 15 รท 3 = 5, and 5 is prime.
- 90 = 2 ร 3 ร 3 ร 5.
In a prime factorisation every factor must be prime. 60 = 4 ร 3 ร 5 is a correct product, but it is not the prime factorisation because 4 is not prime. The answer is 60 = 2 ร 2 ร 3 ร 5.
Which is the prime factorisation of 60?
5Common factors and HCF
A common factor divides both numbers. The biggest one is the HCF โ Highest Common Factor (also called GCD or GCF).
Find the HCF of 36 and 48.
- 36 = 2 ร 2 ร 3 ร 3. 48 = 2 ร 2 ร 2 ร 2 ร 3.
- Primes they share: 2, 2 and 3.
- HCF = 2 ร 2 ร 3 = 12.
Two ribbons are 36 cm and 48 cm long. They are cut into pieces of equal length with nothing left over. What is the greatest possible length of each piece?
- The length must divide both 36 and 48 โ a common factor.
- "Greatest" โ the HCF, which is 12 cm.
- Pieces: 36 รท 12 = 3 and 48 รท 12 = 4, so 7 pieces in all.
What is the greatest number that divides 38 and 62, leaving a remainder of 2 each time?
- Take away the remainder first: 38 โ 2 = 36 and 62 โ 2 = 60. The number divides these exactly.
- HCF of 36 and 60: 36 = 2 ร 2 ร 3 ร 3, 60 = 2 ร 2 ร 3 ร 5 โ 2 ร 2 ร 3 = 12.
- Answer: 12. Check: 38 = 12 ร 3 + 2 โ and 62 = 12 ร 5 + 2 โ
What is the HCF of 18 and 30?
6Common multiples and LCM
A common multiple is a multiple of both numbers. The smallest one is the LCM โ Lowest (Least) Common Multiple.
For LCM(4, 6, 9), write the multiples of 9 โ 9, 18, 27, 36 โ and stop at the first one that 4 and 6 also divide. LCM = 36.
Three bells ring every 6, 8 and 12 minutes. They ring together at 10:00 a.m. When will they next ring together?
- They ring together after a time that is a multiple of 6, 8 and 12 โ the LCM.
- Multiples of 12: 12, 24 โ 24 รท 6 = 4 โ, 24 รท 8 = 3 โ. LCM = 24.
- 10:00 a.m. + 24 minutes = 10:24 a.m.
HCF or LCM? How to choose
| Use HCF whenโฆ | Use LCM whenโฆ |
|---|---|
| cutting or sharing into the greatest / largest equal pieces or groups | finding the smallest / least number that several numbers divide |
| the answer is smaller than (or equal to) the given numbers | things happen again together (bells, lights, buses) |
Golden facts
- HCF ร LCM = product of the two numbers. For 12 and 18: 6 ร 36 = 216 = 12 ร 18.
- The HCF divides the LCM. HCF โค the smaller number; LCM โฅ the larger number.
- For co-prime numbers, HCF = 1 and LCM = their product: LCM(8, 15) = 120.
- If one number divides the other, the smaller is the HCF and the larger is the LCM: HCF(6, 24) = 6, LCM(6, 24) = 24.
The HCF of two numbers is 5 and their LCM is 60. One number is 15. Find the other.
- Product of the numbers = HCF ร LCM = 5 ร 60 = 300.
- Other number = 300 รท 15 = 20.
- Check: HCF(15, 20) = 5 โ, LCM(15, 20) = 60 โ
What is the LCM of 4 and 10?
7Divisibility rules
These tests tell you if a number divides exactly โ without doing the division.
| By | Rule | Example |
|---|---|---|
| 2 | Last digit is even (0, 2, 4, 6, 8) | 4,578 โ |
| 3 | Sum of digits is divisible by 3 | 5,142 โ 5+1+4+2 = 12 โ |
| 4 | Last two digits form a number divisible by 4 (or are 00) | 7,328 โ 28 รท 4 = 7 โ |
| 5 | Last digit is 0 or 5 | 9,845 โ |
| 6 | Divisible by both 2 and 3 | 438 โ even, 4+3+8 = 15 โ |
| 8 | Last three digits form a number divisible by 8 (or are 000) | 7,256 โ 256 รท 8 = 32 โ |
| 9 | Sum of digits is divisible by 9 | 7,821 โ 7+8+2+1 = 18 โ |
| 10 | Last digit is 0 | 8,490 โ |
| 11 | (Sum of digits in odd places) โ (sum in even places), counting from the right, is 0 or a multiple of 11 | 91,806 โ (6+8+9) โ (0+1) = 22 โ |
Combining rules
If a number is divisible by two co-prime numbers, it is divisible by their product: by 2 and 3 โ by 6; by 3 and 4 โ by 12; by 3 and 5 โ by 15.
12 is divisible by 4 and by 6, but not by 24! 4 and 6 share the factor 2, so you cannot just multiply them. The safe answer is their LCM: a number divisible by 4 and 6 must be divisible by 12. Also, every number divisible by 9 is divisible by 3, but not the other way round (12 is divisible by 3, not by 9).
Which number is divisible by 9?
8Missing-digit puzzles
Olympiads hide a digit and ask you to find it. Use the right divisibility rule and try the digits 0 to 9.
Find the digit * so that 5*72 is divisible by 9.
- Sum of known digits: 5 + 7 + 2 = 14.
- The next multiple of 9 after 14 is 18, so * = 18 โ 14 = 4. (27 would need * = 13 โ impossible.)
- Check: 5,472 รท 9 = 608 โ
3*46 is divisible by 3. What are the smallest and greatest possible digits?
- Known digits: 3 + 4 + 6 = 13.
- Sum must be 15, 18 or 21 โ * = 2, 5 or 8.
- Smallest = 2, greatest = 8. (For 3 and 9, answers repeat every 3 or 9 steps.)
What is the smallest digit * that makes 13*6 divisible by 8?
- Only the last three digits matter: 3*6.
- Try: 306 รท 8, 316 รท 8, 326 รท 8 leave remainders; 336 รท 8 = 42 โ
- Smallest digit = 3.
Find * so that 8*62 is divisible by 11.
- Places from the right: 2 (1st), 6 (2nd), * (3rd), 8 (4th).
- Odd places: 2 + *. Even places: 6 + 8 = 14.
- 14 โ (2 + *) must be 0 or 11 โ 12 โ * = 0 or 11 โ * = 12 (impossible) or * = 1.
- Check: 8,162 รท 11 = 742 โ
Which digits can go in 2*4 to make it divisible by 6?
- By 2: it ends in 4, so it is even โ for any digit.
- By 3: 2 + * + 4 = 6 + * must be a multiple of 3 โ * = 0, 3, 6 or 9.
- Numbers: 204, 234, 264, 294 โ all divisible by 6.
What digit makes 7*43 divisible by 11?
A number is divisible by both 4 and 6. It must also be divisible by:
9Watch and explore
- ๐ฎFactor Treesmathplayground.com ยท grow trees to prime factors
- ๐ฎHundreds Charttoytheater.com ยท shade multiples and find primes
- ๐ฎDivisibility and Primesmathigon.org ยท interactive course with puzzles
- ๐Sieve of EratosthenesSimple English Wikipedia ยท the prime-finding trick
- ๐Prime numberSimple English Wikipedia ยท what makes a prime
10Quick recap
- A factor divides a number exactly. Factors come in pairs; there are only a few of them.
- Multiples come from times tables; there are infinitely many. Smallest multiple = the number itself.
- Prime: exactly 2 factors. Composite: more than 2 factors.
- 1 is neither prime nor composite. 2 is the smallest and only even prime.
- There are 25 primes up to 100 (15 of them up to 50).
- Twin primes differ by 2. Co-primes have HCF 1 (they need not be prime).
- Prime factorisation uses only primes: 72 = 2 ร 2 ร 2 ร 3 ร 3.
- HCF = biggest common factor โ "greatest equal pieces". LCM = smallest common multiple โ "together again".
- HCF ร LCM = product of the two numbers.
- 2, 5, 10: last digit. 4: last two digits. 8: last three digits.
- 3 and 9: digit sum. 6: both 2 and 3. 11: alternate-place difference is 0 or a multiple of 11.
- Combine rules only for co-primes (2 ร 3 = 6, 3 ร 4 = 12); 4 and 6 give 12, not 24.